- All primal solutions are obtainable from any dual solution! Paramount is the Fenchel duality Theorem (see previous reference), a monster result for mapping between an arbitrary dual solution and the entire set of primal solutions. You can see it in action here.
- Duality between strong convexity and strong smoothness. Another paper shows a non-trivial and very useful result, Theorem 6 (it's fairly possibly this result was known earlier, but this is another debate...): a closed convex function $R$ is $\beta$-strongly convex w.r.t to a norm $\|.\|$ iff its Fenchel-Legendre transform (aka convex conjugate) $R^*$ is $\frac{1}{\beta}$-strongly smooth w.r.t the dual norm $\|.\|_*$. This result can be invoked to establish the strong convexity of some otherwise rather complicated matrix functions.
Tuesday, August 25, 2015
What is a convex conjugate ?
In case you've missed the convex-optimization revolution (which started with Mureau, Rockafellar, etc., but has pre-history dating back to at least Kuhn, Karush, Tucker, Nash, etc.), the hottest things around are subdifferentials, convex conjugates (aka Fenchel-Legendre transforms), prox operators, and infimal convolutions. Checkout this beautiful one-page manuscript on the subject, by H.H. Bauschke. There are many cool stuff associated with this duality result, here are a few:
Wednesday, July 29, 2015
SpaceNet now available in nilearn master branch + will be available in upcoming release
Hurray!, SpaceNet, a collection of "sparsity + structure" inducing models for brain decoding, is now available in the master branch of nilearn and will be part of the upcoming nilearn release.
For more information on the model, see my OHBM presentation and the many references therewithin.
New paper: computing Nash equilibria in two-person zero-sum games with incomplete information (e.g Texas Hold'em).
In this paper, I'm using some funky ideas from modern (post Jean-Jacques Mureau era) convex analysis to attack the Nash equlibrium problem for these complex games. Read full paper on arXiv.
Tuesday, July 21, 2015
Tuesday, June 30, 2015
Exponentially fast computation of Nash equilibria in matrix games: a weird inequality for polyhedral convex functions
Introduction: General considerations
![]() |
| Example of bounded polyhedron, aka polytope |
We have the following useful characterization (see [section 2, Murota et al. 2013]): $g$ is polyhedral iff there exists a matrix $A = (a_i) \in \mathbb{R}^{m \times n}$ and a vector $c = (c_i) \in \mathbb{R}^m$ s.t $g(x) = \text{max}\{\langle a_i, x \rangle + c_i| 1 \le i \le m\}$, $\forall x \in dom(g)$. As usual, the set $dom(g) := \{x \in \mathbb{R}^p | g(x) < +\infty\}$ is the effective domain of $g$, and is non-empty since $g$ is proper, by assumption. Given a compact convex subset $C \subseteq dom(g)$, let $\mathrm{Opt}_C(g) \subseteq C$ be the set of minimizers of $g$ on $C$. When there is no confusion about the set $C$, we will omit the subscript and simply write $\mathrm{Opt}(g)$. Note that $\mathrm{Opt}_C(g)$ is itself convex.
Minimax for matrix games and the weird inequality
It's not hard to see that the Nash equilibrium problem for a matrix game with payoff matrix $A \in \mathbb{R}^{m \times n}$\begin{eqnarray}
\underset{x \in \Delta_m}{\text{minimize }}\underset{y \in \Delta_n}{\text{maximize }}\langle Ax, y\rangle
\end{eqnarray}
can be written as
\begin{eqnarray}
\underset{(x,y) \in \Delta_m \times \Delta_n}{\text{minimize }}G(x, y),
\end{eqnarray}
where
\begin{eqnarray}
\begin{split}
G(x, y) & := \underset{v \in \Delta_n}{\text{max }}\langle Ax, v\rangle - \underset{u \in \Delta_n}{\text{min }}\langle Au, y\rangle = max\{\langle Ax, v\rangle - \langle Au, y\rangle | (u,v) \in \Delta_m \times \Delta_n\} \\
&= \text{max}\{\langle r_i, [x\text{ }y]^T \rangle | 1 \le i \le m + n\}
\end{split}
\end{eqnarray} is the primal-dual gap function and $(r_i) = R := \begin{bmatrix}0\hspace{1.5em}A\\-A^T\hspace{.4em}0\end{bmatrix} \in \mathbb{R}^{(m+n)^2}$. Thus $G$ is a polyhedral convex function on $\Delta_m \times \Delta_n$. Note that $G(x, y) \ge 0$ for every pair of strategies $(x, y) \in \Delta_m \times \Delta_n$, with equality iff $(x,y) \in \mathrm{Opt}(G)$. Also note that the elements of $\mathrm{Opt}(G)$ are simply the Nash equilibria of the game.
Definition. For a given tolerance $\epsilon > 0$, we call a pair of strategies $(x^*,y^*) \in \Delta_m \times \Delta_n$ a Nash $\epsilon$-equilibrium if $G(x^*, y^*) \le \epsilon$.
A remarkable result by [Andrew Gilpin et al.] (Lemma 3) says that for any matrix game, there exists a scalar $\delta > 0$ such that
\begin{eqnarray} \mathrm{dist}((x, y), \mathrm{Opt}(G)) \le \dfrac{G(x, y)}{\delta}, \forall (x, y) \in \Delta_m \times \Delta_n, \label{eq:weirdo}
\end{eqnarray}
where $\mathrm{dist}((x, y), \mathrm{Opt}(G)) := \mathrm{min}\{\|(u,v) - (x,y)\|| (u, v) \in \mathrm{Opt}(G)\}$ is the distance of $(x, y)$ from $\mathrm{Opt}(G)$. Using this bound in conjunction with Nesterov smoothing, the authors derived an $\mathcal{O}\left(\left(\|A\| / \delta\right) ln\left(1 / \epsilon\right)\right)$ algorithm for computing a Nash $\epsilon$-equilibrium. Note however that, the suprimum of the $\delta$s veryfin \eqref{eq:weirdo} can be arbitrarily small in fact, we can explicitly construct games for which it is arbitrarily close to $0$), and so the exponential speed may not be experienced empirically on some ill-conditioned games. To be continued...
Monday, June 29, 2015
PRNI & OHBM 2015
PRNI 2015 @ stanford was great! Great keynotes (Candès, Tibshirani, etc.) + great place. OHBM in Honolulu, well the idea alone seams surreal. Hawaii is marvelous. Great conference too.
These are slides for my
Here are some photos.The future of screening
![]() |
| Feature-screening à la [Dohmatob et al. PRNI2015] |
We also present resent work on heuristc univariate screening [Dohmatob et al. PRNI2015].
Notation
For a vector $v \in \mathbb{R}^p$, we recall the definition of its- $l_1$-norm $\|v\|_1 := \sum_{1 \le j \le p}|v_j|$,
- $l_2$-norm $\|v\|_2 := (\sum_{1 \le j \le p}|v_j|^2)^{1/2}$, and
- $l_{\infty}$-norm $\|v\|_{\infty} := \max_{1 \le j \le p}|v_j|$.
General considerations
Consider a Lasso model with response vector $y \in \mathbb{R}^p$ and design matrix $X \in \mathbb{R}^{n \times p}$. Let $\lambda$ (with $0 < \lambda < \|X^Ty\|_{\infty}$) be the regularization parameter. The primal objective to be minimized as a function of the primal variable $\beta \in \mathbb{R}^p$ ($\beta$ is the vector of regressor coefficients) is \begin{eqnarray} p_{\lambda}(\beta) := \frac{1}{2}\|X\beta - y\|^2_2 + \lambda\|\beta\|_1 \label{eq:primal} \end{eqnarray} In the sense of Fenchel-Rockafellar, the dual objective to be maximized as a function of the dual variable $\theta \in \mathbb{R}^n$ is \begin{eqnarray} d_{\lambda}(\theta) := \begin{cases} \frac{1}{2}\|y\|^2_2 - \frac{\lambda^2}{2}\|\theta - \frac{y}{\lambda}\|^2_2, &\mbox{if } \|X^T\theta\|_{\infty} \le 1\\ -\infty, &\mbox{otherwise}. \end{cases} \label{eq:dual} \end{eqnarray} Finally, the duality-gap $\delta_{\lambda}(\beta, \theta)$ at $(\beta, \theta)$ is defined by \begin{eqnarray} \delta_{\lambda}(\beta, \theta) := p_{\lambda}(\beta) - d_{\lambda}(\theta). \label{eq:dgap} \end{eqnarray} One notes the following straightforward facts- $\delta_{\lambda}(\beta, \theta) \ge 0$ with equality iff $\beta$ minimizes \eqref{eq:primal} and $\theta$ maximizes \eqref{eq:dual}. Such a primal-dual pair is called an optimal pair.
- Construct a ``small'' compact set $C \subseteq \mathbb{R}^n$, containing the dual optimal point $\theta_{\lambda}^*$ with $C \cap \mathcal{P} \ne \emptyset$, such that the value maximum value $m_{C,j} := \underset{\theta \in C}{max}\text{ }|X^T_j\theta|$ can be easily computed.
- Noting that $m_{C,j}$ is an upper bound for $|X^T_j\theta^*_{\lambda}|$ in \eqref{eq:fundamental}, we may then discard all features $j$ for which $m_{C,j} < 1$.
Safe sphere tests
We start with the following lemma which provides a useful formula for the duality-gap $\delta_{\lambda}(\beta, \theta)$ defined in \eqref{eq:dgap}.
For every $(\beta, \theta) \in \mathbb{R}^p \times \mathbb{R}^n$, we
have
\begin{eqnarray}
\delta_{\lambda}(\beta, \theta) = \begin{cases}
\frac{\lambda^2}{2}\left\|\theta -
(y-X\beta)/\lambda\right\|^2_2 + \lambda\left(\|\beta\|_1 -
\theta^TX\beta\right), &\mbox{if } \theta \in \mathcal{P}\\
+\infty, &\mbox{otherwise}.
\end{cases}
\label{eq:dgap_formula}
\end{eqnarray}
Expand the formula in \eqref{eq:dgap}, and then complete the square
w.r.t $\theta$.
Let $(\beta, \theta) \in \mathbb{R}^p \times \mathcal{P}$
be a feasible primal-dual pair. If $\theta_{\lambda}^*$ is an optimal
dual point (i.e maximizes the dual objective $p_{\lambda}$ defined in
\eqref{eq:dual}), then for every other dual point $\theta \in
\mathbb{R}^n$ it holds that
\begin{eqnarray}
\left\|\theta_{\lambda}^* -
(y-X\beta)/\lambda\right\|_2 \le
\sqrt{2\delta_{\lambda}(\beta, \theta)}/\lambda.
\label{eq:dual_sphere}
\end{eqnarray}
By the optimality of $\theta_{\lambda}^*$ for the ``marginal''
duality-gap function $\eta \mapsto \delta_{\lambda}(\beta, \eta)$, we
have
\begin{eqnarray}
\delta_{\lambda}(\beta, \theta_{\lambda}^*) \le
\delta_{\lambda}(\beta, \theta).
\label{eq:dgap_ineq}
\end{eqnarray}
Now observe that $\theta_{\lambda}^*$, being the projection of the point
$y/\lambda$ onto the dual-feasible polyhedron $\mathcal{P}$, lies on
the boundary of $\mathcal{P}$ because the latter doesn't contain
$y/\lambda$ since $\lambda < \|X^Ty\|_{\infty}$. Thus we have
$\|X^T\theta_{\lambda}^*\|_{\infty} = 1$, and by Holder's inequality
it follows that
\begin{eqnarray}
\|\beta\|_1 - \beta^TX^T\theta_{\lambda}^* =
\|\beta\|_1\|X^T\theta_{\lambda}^*\|_{\infty} -
\beta^TX^T\theta_{\lambda}^* \ge 0.
\label{eq:holder}
\end{eqnarray}
Finally, invoking formula \eqref{eq:dgap_formula} on the LHS of
\eqref{eq:dgap_ineq} and using \eqref{eq:holder} completes the proof.
Given a feasible primal-dual pair
$(\beta, \theta) \in \mathbb{R}^p \times \mathcal{P}$, the above theorem prescribes a trust-region for the optimal dual point
$\theta_{\lambda}^*$, namely the sphere $S_n(y - X\beta)/\lambda,
\sqrt{2\delta_{\lambda}(\beta, \theta)}/\lambda)$.
Static safe sphere test
Let's begin with the following elementary but important lemma about the maximum value of the function $\theta \mapsto |b^T\theta|$ on the sphere \begin{eqnarray} S_n(c,r) := \{\theta \in \mathbb{R}^n | \|\theta - c\|_2 \le r\}, \end{eqnarray} of center $c \in \mathbb{R}^n$ and radius $r > 0$. Viz,
\begin{eqnarray}
\underset{\theta \in S_n(c, r)}{max}\text{ }|b^T\theta| = |b^Tc| +
r\|b\|_2.
\label{eq:max_sphere}
\end{eqnarray}
One has
\begin{eqnarray*}
\underset{\theta \in S_n(c, r)}{max}\text{ }b^T\theta =
\underset{\theta \in S_n(0, r)}{max}\text{ }b^T(\theta + c) = b^Tc +
r\underset{\theta \in S_n(0, 1)}{max}\text{ }b^T\theta = b^Tc +
r\|b\|_2.
\end{eqnarray*}
Replacing $b$ with $-b$ in the above equation yields
\begin{eqnarray*}
\underset{\theta \in S_n(c, r)}{max}-b^T\theta = -b^Tc +
r\|b\|_2.
\end{eqnarray*}
Now, combining both equations and using the fact that
\begin{eqnarray*}
|b^T\theta| \equiv max(b^T\theta, -b^T\theta),
\end{eqnarray*}
we obtain the desired result.
The following lemma is from [Xiang et al. 2014].
Given a safe sphere $S_n(c, r)$ for the optimal dual point
$\theta_{\lambda}^*$, the following screening rule is safe
\begin{eqnarray}
\text{Discard the } j\text{th feature if }
|X_j^Tc| + r\|X_j^T\|_2 < 1.
\label{eq:sphere_test}
\end{eqnarray}
Direct application of \eqref{eq:fundamental} and
\eqref{eq:max_sphere}.
Using the trust-region \eqref{eq:dual_sphere} established in the previous theorem for the optimal dual variable
$\theta_{\lambda}^*$, namely the sphere $S_n\left((y-X\beta)/\lambda,
\sqrt{2\delta_{\lambda}(\beta,\theta)}/\lambda\right)$, we can
envisage to device a screening rule in the form
\eqref{eq:sphere_test}. Indeed,
For any primal-dual pair $(\beta,\theta) \in \mathbb{R}^p \times
\mathbb{R}^n$, the rule
\begin{eqnarray}
\text{Discard the } j\text{th feature if }
\left|X_j^T(y-X\beta)\right| +
\sqrt{2\delta_{\lambda}(\beta,\theta)}\|X_j^T\|_2 < \lambda
\label{eq:sphere_test_actual}
\end{eqnarray}
is safe.
Use the last lemma, on the safe sphere
$S_n\left((y-X\beta)/\lambda,
\sqrt{2\delta_{\lambda}(\beta,\theta)}/\lambda\right)$ obtained in
the previous theorem.
Dynamic safe sphere test
The results presented here are due to very recent work by Gramfort and co-workers. The screening rule in \eqref{eq:sphere_test_actual} only makes sense (i.e there is any hope it could ever screen some features) only if $\delta_{\lambda}(\beta,\theta) < +\infty$, i.e only if $\theta$ is dual-feasible. In fact, the smaller the duality-gap $\delta_{\lambda}(\beta,\theta)$, the more effective the screening rule is. Thus we need a procedure which, given a primal point $\beta \in \mathbb{R}^p$, generates a dual-feasible point $\theta$ for which $\delta_{\lambda}(\beta,\theta)$ is as small as possible. As was first mentioned in [Bonnefoy et al. 2014], any iterative solver for \eqref{eq:primal} can be used to produce a sequence of primal-dual feasible pairs $(\beta^{(k)}, \theta^{(k)}) \in \mathbb{R}^p \times \mathcal{P}$, and a decreasing sequence of safe spheres $S_n\left(y / \lambda, \|\theta^{(k)} - y / \lambda\right\|_2)$. Indeed for each primal iterate $\beta^{(k)}$, one finds a scalar $\mu^{(k)} \in \mathbb{R}$ such that $\mu^{(k)} (y - X\beta^{(k)}) \in \mathcal{P}$ is the dual-feasible point closest to $y / \lambda$. This sub-problem is a simple minimization problem of quadratic function $\mu \mapsto \|\mu(y-X\beta^{(k)}) - y / \lambda\|^2_2$ on a closed real interval $\left[-\frac{1}{\|X^T(y - X\beta^{(k)})\|_{\infty}}, \frac{1}{\|X^T(y - X\beta^{(k)})\|_{\infty}}\right]$, with an analytic solution \begin{eqnarray} \mu^{(k)} = \begin{cases} \left[\frac{y^T(y-X\beta^{(k)})}{\lambda \|y-X\beta^{(k)}\|_2^2}\right]^{-\frac{1}{\|X^T(y - X\beta^{(k)})\|_{\infty}}}_{\frac{1}{\|X^T(y - X\beta^{(k)})\|_{\infty}}}, &\mbox{if } X\beta^{(k)} \ne y\\ 1, &\mbox{otherwise}. \end{cases} \end{eqnarray} The resulting algorithm ("Poorman's FISTA with dynamic screening") is depicted below.- Input: $\lambda \in \text{ }]0, \|X^Ty\|_{\infty}[$ the regularization parameter; $\epsilon > 0$ the desired precision on duality gap.\\
- Initialize: $\beta^{(0)} \leftarrow 0 \in \mathbb{R}^p$, $\theta^{(0)} \leftarrow y/\lambda \in \mathcal{P}$, $\delta^{(0)} \leftarrow+\infty$, $t^{(0)} \leftarrow 1$, and $k \leftarrow 0$.
- Repeat (until $\delta^{(k)} < \epsilon$):
- $\beta^{(k + 1)} \leftarrow soft_{\lambda/L}(\eta^{(k)} - X^T(X\eta^{(k)} - y)), \hspace{.5em}\theta^{(k+1)} \leftarrow \mu^{(k+1)}(y - X\beta^{(k+1)})$
- $t^{(k+1)} \leftarrow \frac{1 + \sqrt{4t^{(k)} + 1}}{2}, \hspace{.5em}\eta^{(k+1)} \leftarrow \beta^{(k+1)} + \frac{t^{(k)} - 1}{t^{(k+1)}}(\beta^{(k+1)} - \beta^{(k)})$
- $\delta^{(k+1)} \leftarrow \frac{\lambda^2}{2}\left\|\theta^{(k+1)} - (y-X\beta^{(k+1)})/\lambda\right\|^2_2 + \lambda\left(\|\beta^{(k+1)}\|_1 - \theta^TX\beta^{(k + 1)}\right)$
- $X, \beta^{(k+1)}, \eta^{(k+1)} \leftarrow screen(X,y,\beta^{(k+1)}, \eta^{(k+1)}, \delta^{(k+1)})$
- $k \leftarrow k + 1$
- Return $\beta^{(k)}$
- One can show that the above dynamic screening procedure those no harm to the convergence theory the iterative solver.
- A coordinate-descent solver would be more appropriate. We presented FISTA here for simplicity rather than applicability
Univariate (heuristic) screening for brain decoding problems
In [Dohmatob et al. PRNI2015], we proposed (amongst other tricks) a univariate heuristic for detecting and disregarding irrelevant voxels in brain decoding problem (ssee figure above). This heuristic can result in upto 10-fold speedup over full-brain analysis. Get a quick overview here.
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